Simple C++ lottery program @KTSI

One response

1. 

   Jamelle Comfort

   April 25, 2012

   Could you tell what I am doing wrong on this program. I am only getting two integers. I want the loop to perform five times and calculate r = rand_0toN1(56) + 1 and on the sixth time perform s = rand_0toN1(46) +1.
   I am only getting to two integers.

   // Test.cpp : main project file.

   #include “stdafx.h”
   #include “iostream”
   #include “stdlib.h”
   #include “time.h”
   #include “math.h”
   using namespace std;

   //Declare functions before starting.
   int rand_0toN1(int n);
   void pick_a_number();

   int main() {
   int i;
   int n;

   srand(time(NULL)); //Set seed for random numbers.

   cout << "Enter number of trials to run ";
   cout <> n;

   for( i = 1; i <= n; i++) {
   pick_a_number();
   }
   return 0;
   }
   //Pick_a_number function
   //Performs picking one num by getting a random 1-56 and
   //a random 1-46. These are then used to index the string arrays,
   // rows.
   void pick_a_number() {
   int i;
   int r; //Random index (1 thru 56)
   int s; //Random index (1 thru 46)
   i = 0;
   while (i < 6) {
   if (i != 6)
   r = rand_0toN1(56) + 1;
   else if (i == 6)
   s = rand_0toN1(46) + 1;
   i++;
   }
   cout << r << " " << s << " "; //Print out results.
   }
   //Random 1-to-N function.
   //Generate a random integer from 1 to N, giving each
   //integer an equal probability.
   int rand_0toN1(int n) {
   return (rand() % n) + 1;
   }

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